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Bravo!

Answer
:
16
correct, 10 incorrect
Let's denote the number of correct answers as ( C )
and the number of
incorrect answers as ( I ). The father pays $5.00 for
each correct
answer and receives $8.00 for each incorrect answer.
The total amount the father pays is \( 5C \), and the total amount the
son pays is ( 8I ).
According to the problem, no money was exchanged, so: [ 5C - 8I =
0 ]
Now, we know that the boy answered a total of 26 questions:
[ C + I = 26 ]
Now, we have a system of two equations:
[ begin{cases} 5C - 8I = 0
C + I = 26 end{cases} ]
We can solve this system to find the values of ( C )
and I ).
One way to solve it is to multiply the second equation by 8 and add it
to the first equation to eliminate ( I ):
[ \begin{cases} 5C - 8I = 0 \\ 8(C + I) = 8 times
26 end{cases} ]
This simplifies to:
[ begin{cases} 5C - 8I = 0 8C + 8I =
208 end{cases} ]
Now, add the two equations:
[ 5C - 8I + 8C + 8I = 0 + 208 ]
Combine like terms:[ 13C = 208 ]
Divide by 13:
[ C = 16 ]
Now that we know ( C ), substitute it back into the
second equation to find ( I ):
[ 16 + I = 26 ]
Subtract 16 from both sides:
[ I = 10 ]
So, the boy got 16
correct answers and 10 incorrect answers. |
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