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Math Challenge
Thanks Archimedes

Father of math

Answer:
 M = 4,   A = 7,   T = 2,   H = 5

Selon Daniel

De la dernière ligne on peut déduire que H vaut 15/3 = 5

Donc la première ligne devient M + A + T = 13

D’où la déduction que M = 4 puisque 2M + A + T = 17

Si M = 4 et H = 5 donc en fonction de la ligne 3 A = 7 puisque 16 – M – H = 7

De la troisième ligne on déduit que si M + A = 11 donc M vaut bien 4 et A vaut bien 7

Or si M + A + T + H = 18 et que M + A + H = 16 donc T = 2

Vérifions:

M(4) + A(7) + T(2) + H(5) =18

2M(8) + A(7) + T(2) = 17

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