Answer :
The only set of
three numbers, of two, three, and
five figures
respectively, that will fulfil the required conditions is 27
× 594 =
16,038.
These three numbers contain all the nine digits and 0, without
repetition; the first two numbers multiplied together make the third,
and
the second is exactly twentytwo times the first.
If
the numbers might
contain one, four, and five figures respectively, there would be many
correct answers, such as 3 × 5,694 = 17,082; but it is a
curious fact
that there is only one answer to the problem as propounded, though it
is
no easy matter to prove that this is the case.
