He made a rough
diagram, and placed a crown and a
two of the
divisions, as indicated in the illustration.
he continued, "place
the fewest possible
the seven empty divisions, so that each of the three columns, three
and two diagonals shall add up fifteen shillings.
Of course, no
may be without at least one coin, and no two divisions may contain the
how can the coins affect
the question?" asked
"That you will find out when you approach the
"I shall do it with numbers first," said
Hawkhurst, "and then
minutes later, however,
he exclaimed, "Hang
it all! I
getting the 2 in a corner.
May the florin be moved from its present
I give it up."
Grigsby and I decided that
we would work at it
time, so he showed Hawkhurst the solution privately'